Lexicographical Order

We define the following terms:

• Lexicographical Order, also known as alphabetic or dictionary order, orders characters as follows:
  

  For example, ball < cat, dog < dorm, Happy < happy, Zoo < ball.

• A substring of a string is a contiguous block of characters in the string. For example, the substrings of abc are a, b, c, ab, bc, and abc.

Given a string, , and an integer, , complete the function so that it finds the lexicographically smallest and largest substrings of length .

Input Format

The first line contains a string denoting .
The second line contains an integer denoting .

Constraints

•  consists of English alphabetic letters only (i.e., [a-zA-Z]).

Output Format

Return the respective lexicographically smallest and largest substrings as a single newline-separated string.

Sample Input 0

welcometojava

3

Sample Output 0

ava

wel

Explanation 0

String  has the following lexicographically-ordered substrings of length :

[ ''ava'',''com'', ''elc'', ''eto'',''jav'',''lco'',''met'',''ome'',''oja'',toj'',''wel'' ]

We then return the first (lexicographically smallest) substring and the last (lexicographically largest) substring as two newline-separated values (i.e., ava\nwel).

The stub code in the editor then prints ava as our first line of output and wel as our second line of output.

Program:

import java.util.Scanner;

public class Solution {

    public static String getSmallestAndLargest(String s, int k) 

    {

        String substring = s.substring(0, k);

        String smallest = substring;

        String largest = substring;

        

        for (int i = 1; i <= s.length() - k; i++) 

        {

            // Create a substring of length 'k'

            substring = s.substring(i, i + k);

                

            // If current substring is lexicographically smaller than 'smallest'

            if (substring.compareTo(smallest) < 0) 

            {

                smallest = substring;

            }

            // If current substring is lexicographically larger than 'largest'

            if (substring.compareTo(largest) > 0) 

            {

                largest = substring;

            }

        }

        

        return smallest + "\n" + largest;

    }

    

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);

        String s = scan.next();

        int k = scan.nextInt();

        scan.close();

      

        System.out.println(getSmallestAndLargest(s, k));

    }

}